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2/3s+150=s
We move all terms to the left:
2/3s+150-(s)=0
Domain of the equation: 3s!=0We add all the numbers together, and all the variables
s!=0/3
s!=0
s∈R
-1s+2/3s+150=0
We multiply all the terms by the denominator
-1s*3s+150*3s+2=0
Wy multiply elements
-3s^2+450s+2=0
a = -3; b = 450; c = +2;
Δ = b2-4ac
Δ = 4502-4·(-3)·2
Δ = 202524
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{202524}=\sqrt{4*50631}=\sqrt{4}*\sqrt{50631}=2\sqrt{50631}$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(450)-2\sqrt{50631}}{2*-3}=\frac{-450-2\sqrt{50631}}{-6} $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(450)+2\sqrt{50631}}{2*-3}=\frac{-450+2\sqrt{50631}}{-6} $
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