2/3u+2/3+1/5u=2/3u

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Solution for 2/3u+2/3+1/5u=2/3u equation:



2/3u+2/3+1/5u=2/3u
We move all terms to the left:
2/3u+2/3+1/5u-(2/3u)=0
Domain of the equation: 3u!=0
u!=0/3
u!=0
u∈R
Domain of the equation: 5u!=0
u!=0/5
u!=0
u∈R
Domain of the equation: 3u)!=0
u!=0/1
u!=0
u∈R
We add all the numbers together, and all the variables
2/3u+1/5u-(+2/3u)+2/3=0
We get rid of parentheses
2/3u+1/5u-2/3u+2/3=0
We calculate fractions
(-10u+2)/135u^2+27u/135u^2+10u/135u^2=0
We multiply all the terms by the denominator
(-10u+2)+27u+10u=0
We add all the numbers together, and all the variables
37u+(-10u+2)=0
We get rid of parentheses
37u-10u+2=0
We add all the numbers together, and all the variables
27u+2=0
We move all terms containing u to the left, all other terms to the right
27u=-2
u=-2/27
u=-2/27

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