2/3x(x+3)=2/3x(x-6)

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Solution for 2/3x(x+3)=2/3x(x-6) equation: 



2/3x(x+3)=2/3x(x-6)

We move all terms to the left:

2/3x(x+3)-(2/3x(x-6))=0



Domain of the equation: 3x(x+3)!=0

x∈R





Domain of the equation: 3x(x-6))!=0

x∈R



We calculate fractions


(6xx/(3x(x+3)*3x(x-6)))+(-6xx/(3x(x+3)*3x(x-6)))=0



We calculate terms in parentheses: +(6xx/(3x(x+3)*3x(x-6))), so:

6xx/(3x(x+3)*3x(x-6))

We multiply all the terms by the denominator


6xx

Back to the equation:

+(6xx)





We calculate terms in parentheses: +(-6xx/(3x(x+3)*3x(x-6))), so:

-6xx/(3x(x+3)*3x(x-6))

We multiply all the terms by the denominator


-6xx

Back to the equation:

+(-6xx)



We get rid of parentheses

6xx-6xx=0

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