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2/3x(x-12)=x+8
We move all terms to the left:
2/3x(x-12)-(x+8)=0
Domain of the equation: 3x(x-12)!=0We get rid of parentheses
x∈R
2/3x(x-12)-x-8=0
We multiply all the terms by the denominator
-x*3x(x-12)-8*3x(x-12)+2=0
Wy multiply elements
-3x^2(x-24x(x+2=0
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