2/3x+(-4)=8

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Solution for 2/3x+(-4)=8 equation: 



2/3x+(-4)=8

We move all terms to the left:

2/3x+(-4)-(8)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



determiningTheFunctionDomain
2/3x-8+(-4)=0

We add all the numbers together, and all the variables

2/3x-12=0

We multiply all the terms by the denominator


-12*3x+2=0

Wy multiply elements

-36x+2=0

We move all terms containing x to the left, all other terms to the right

-36x=-2

x=-2/-36

x=1/18

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