2/3x+-5=1/2x+-3

Solution for 2/3x+-5=1/2x+-3 equation:

2/3x+-5=1/2x+-3

We move all terms to the left:

2/3x+-5-(1/2x+-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x+-3)!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(1/2x-3)-5+=0

We add all the numbers together, and all the variables

2/3x-(1/2x-3)=0

We get rid of parentheses

2/3x-1/2x+3=0

We calculate fractions


4x/6x^2+(-3x)/6x^2+3=0

We multiply all the terms by the denominator


4x+(-3x)+3*6x^2=0

Wy multiply elements

18x^2+4x+(-3x)=0

We get rid of parentheses

18x^2+4x-3x=0

We add all the numbers together, and all the variables

18x^2+x=0

a = 18; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·18·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*18}=\frac{-2}{36}
=-1/18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*18}=\frac{0}{36}
=0
$