2/3x+1/2x-4=3

Solution for 2/3x+1/2x-4=3 equation:

2/3x+1/2x-4=3

We move all terms to the left:

2/3x+1/2x-4-(3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x+1/2x-7=0

We calculate fractions


4x/6x^2+3x/6x^2-7=0

We multiply all the terms by the denominator


4x+3x-7*6x^2=0

We add all the numbers together, and all the variables

7x-7*6x^2=0

Wy multiply elements

-42x^2+7x=0

a = -42; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-42)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-42}=\frac{-14}{-84}
=1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-42}=\frac{0}{-84}
=0
$