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2/3x+1/5x=180
We move all terms to the left:
2/3x+1/5x-(180)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
10x/15x^2+3x/15x^2-180=0
We multiply all the terms by the denominator
10x+3x-180*15x^2=0
We add all the numbers together, and all the variables
13x-180*15x^2=0
Wy multiply elements
-2700x^2+13x=0
a = -2700; b = 13; c = 0;
Δ = b2-4ac
Δ = 132-4·(-2700)·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-13}{2*-2700}=\frac{-26}{-5400} =13/2700 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+13}{2*-2700}=\frac{0}{-5400} =0 $
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