2/3x+10=746/75+3/5x

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Solution for 2/3x+10=746/75+3/5x equation: 


x in (-oo:+oo)

(2/3)*x+10 = (3/5)*x+746/75 // - (3/5)*x+746/75

(2/3)*x-((3/5)*x)-(746/75)+10 = 0

(2/3)*x+(-3/5)*x-746/75+10 = 0

1/15*x+4/75 = 0 // - 4/75

1/15*x = -4/75 // : 1/15

x = -4/75/1/15

x = -4/5

x = -4/5

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