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2/3x+3+4x=-4
We move all terms to the left:
2/3x+3+4x-(-4)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
4x+2/3x+7=0
We multiply all the terms by the denominator
4x*3x+7*3x+2=0
Wy multiply elements
12x^2+21x+2=0
a = 12; b = 21; c = +2;
Δ = b2-4ac
Δ = 212-4·12·2
Δ = 345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{345}}{2*12}=\frac{-21-\sqrt{345}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{345}}{2*12}=\frac{-21+\sqrt{345}}{24} $
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