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2/3x+3/2+1/5x=2/3x
We move all terms to the left:
2/3x+3/2+1/5x-(2/3x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0
x!=0/5
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x+1/5x-(+2/3x)+3/2=0
We get rid of parentheses
2/3x+1/5x-2/3x+3/2=0
We calculate fractions
225x^2/60x^2+(-40x+2)/60x^2+12x/60x^2=0
We multiply all the terms by the denominator
225x^2+(-40x+2)+12x=0
We add all the numbers together, and all the variables
225x^2+12x+(-40x+2)=0
We get rid of parentheses
225x^2+12x-40x+2=0
We add all the numbers together, and all the variables
225x^2-28x+2=0
a = 225; b = -28; c = +2;
Δ = b2-4ac
Δ = -282-4·225·2
Δ = -1016
Delta is less than zero, so there is no solution for the equation
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