2/3x+3/2x+9=9/2x-4

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Solution for 2/3x+3/2x+9=9/2x-4 equation:



2/3x+3/2x+9=9/2x-4
We move all terms to the left:
2/3x+3/2x+9-(9/2x-4)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 2x-4)!=0
x∈R
We get rid of parentheses
2/3x+3/2x-9/2x+4+9=0
We calculate fractions
4x/6x^2+(-27x+3)/6x^2+4+9=0
We add all the numbers together, and all the variables
4x/6x^2+(-27x+3)/6x^2+13=0
We multiply all the terms by the denominator
4x+(-27x+3)+13*6x^2=0
Wy multiply elements
78x^2+4x+(-27x+3)=0
We get rid of parentheses
78x^2+4x-27x+3=0
We add all the numbers together, and all the variables
78x^2-23x+3=0
a = 78; b = -23; c = +3;
Δ = b2-4ac
Δ = -232-4·78·3
Δ = -407
Delta is less than zero, so there is no solution for the equation

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