2/3x+3/4x=17

Solution for 2/3x+3/4x=17 equation:

2/3x+3/4x=17

We move all terms to the left:

2/3x+3/4x-(17)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We calculate fractions


8x/12x^2+9x/12x^2-17=0

We multiply all the terms by the denominator


8x+9x-17*12x^2=0

We add all the numbers together, and all the variables

17x-17*12x^2=0

Wy multiply elements

-204x^2+17x=0

a = -204; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·(-204)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*-204}=\frac{-34}{-408}
=1/12
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*-204}=\frac{0}{-408}
=0
$