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2/3x+5-1/4x=-15
We move all terms to the left:
2/3x+5-1/4x-(-15)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
2/3x-1/4x+20=0
We calculate fractions
8x/12x^2+(-3x)/12x^2+20=0
We multiply all the terms by the denominator
8x+(-3x)+20*12x^2=0
Wy multiply elements
240x^2+8x+(-3x)=0
We get rid of parentheses
240x^2+8x-3x=0
We add all the numbers together, and all the variables
240x^2+5x=0
a = 240; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·240·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*240}=\frac{-10}{480} =-1/48 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*240}=\frac{0}{480} =0 $
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