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2/3x+5=2/3(x-3)
We move all terms to the left:
2/3x+5-(2/3(x-3))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3(x-3))!=0We calculate fractions
x∈R
(6xx/(9x^2x+(-(2*3x)/(9x^2x+5=0
We can not solve this equation
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