2/3x+5=2x+11

Solution for 2/3x+5=2x+11 equation:

2/3x+5=2x+11

We move all terms to the left:

2/3x+5-(2x+11)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x-2x-11+5=0

We multiply all the terms by the denominator


-2x*3x-11*3x+5*3x+2=0

Wy multiply elements

-6x^2-33x+15x+2=0

We add all the numbers together, and all the variables

-6x^2-18x+2=0

a = -6; b = -18; c = +2;
Δ = b2-4ac
Δ = -182-4·(-6)·2
Δ = 372
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{372}=\sqrt{4*93}=\sqrt{4}*\sqrt{93}=2\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{93}}{2*-6}=\frac{18-2\sqrt{93}}{-12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{93}}{2*-6}=\frac{18+2\sqrt{93}}{-12}
$