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2/3x+6=2(x+1)
We move all terms to the left:
2/3x+6-(2(x+1))=0
Domain of the equation: 3x!=0We multiply all the terms by the denominator
x!=0/3
x!=0
x∈R
-((2(x+1)))*3x+6*3x+2=0
Wy multiply elements
-((2(x+1)))*3x+18x+2=0
We add all the numbers together, and all the variables
18x-((2(x+1)))*3x+2=0
We move all terms containing x to the left, all other terms to the right
18x-((2(x+1)))*3x=-2
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