2/3x+7+1/6x=1/2

Solution for 2/3x+7+1/6x=1/2 equation:

2/3x+7+1/6x=1/2

We move all terms to the left:

2/3x+7+1/6x-(1/2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x!=0

x!=0/6

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x+1/6x+7-(+1/2)=0

We get rid of parentheses

2/3x+1/6x+7-1/2=0

We calculate fractions


(-108x^2)/72x^2+48x/72x^2+12x/72x^2+7=0

We multiply all the terms by the denominator


(-108x^2)+48x+12x+7*72x^2=0

We add all the numbers together, and all the variables

(-108x^2)+60x+7*72x^2=0

Wy multiply elements

(-108x^2)+504x^2+60x=0

We get rid of parentheses

-108x^2+504x^2+60x=0

We add all the numbers together, and all the variables

396x^2+60x=0

a = 396; b = 60; c = 0;
Δ = b2-4ac
Δ = 602-4·396·0
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-60}{2*396}=\frac{-120}{792}
=-5/33
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+60}{2*396}=\frac{0}{792}
=0
$