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2/3x+7/3x=3x
We move all terms to the left:
2/3x+7/3x-(3x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-3x+2/3x+7/3x=0
We multiply all the terms by the denominator
-3x*3x+2+7=0
We add all the numbers together, and all the variables
-3x*3x+9=0
Wy multiply elements
-9x^2+9=0
a = -9; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-9)·9
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-18}{2*-9}=\frac{-18}{-18} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+18}{2*-9}=\frac{18}{-18} =-1 $
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