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2/3x+7=0.45x-11
We move all terms to the left:
2/3x+7-(0.45x-11)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-0.45x+11+7=0
We multiply all the terms by the denominator
-(0.45x)*3x+11*3x+7*3x+2=0
We add all the numbers together, and all the variables
-(+0.45x)*3x+11*3x+7*3x+2=0
We multiply parentheses
-0x^2+11*3x+7*3x+2=0
Wy multiply elements
-0x^2+33x+21x+2=0
We add all the numbers together, and all the variables
-1x^2+54x+2=0
a = -1; b = 54; c = +2;
Δ = b2-4ac
Δ = 542-4·(-1)·2
Δ = 2924
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2924}=\sqrt{4*731}=\sqrt{4}*\sqrt{731}=2\sqrt{731}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-2\sqrt{731}}{2*-1}=\frac{-54-2\sqrt{731}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+2\sqrt{731}}{2*-1}=\frac{-54+2\sqrt{731}}{-2} $
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