2/3x+7=1/6(4x+42)

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Solution for 2/3x+7=1/6(4x+42) equation: 



2/3x+7=1/6(4x+42)

We move all terms to the left:

2/3x+7-(1/6(4x+42))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 6(4x+42))!=0

x∈R



We calculate fractions


(12x4/(18x^24+(-(1*3x)/(18x^24+7=0

We do not support expression: x^24

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