2/3x+7=7+-x

Solution for 2/3x+7=7+-x equation:

2/3x+7=7+-x

We move all terms to the left:

2/3x+7-(7+-x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(-1x)+7=0

We get rid of parentheses

2/3x+1x+7=0

We multiply all the terms by the denominator


1x*3x+7*3x+2=0

Wy multiply elements

3x^2+21x+2=0

a = 3; b = 21; c = +2;
Δ = b2-4ac
Δ = 212-4·3·2
Δ = 417
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{417}}{2*3}=\frac{-21-\sqrt{417}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{417}}{2*3}=\frac{-21+\sqrt{417}}{6}
$