2/3x+8=4x-2

Solution for 2/3x+8=4x-2 equation:

2/3x+8=4x-2

We move all terms to the left:

2/3x+8-(4x-2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x-4x+2+8=0

We multiply all the terms by the denominator


-4x*3x+2*3x+8*3x+2=0

Wy multiply elements

-12x^2+6x+24x+2=0

We add all the numbers together, and all the variables

-12x^2+30x+2=0

a = -12; b = 30; c = +2;
Δ = b2-4ac
Δ = 302-4·(-12)·2
Δ = 996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{996}=\sqrt{4*249}=\sqrt{4}*\sqrt{249}=2\sqrt{249}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-2\sqrt{249}}{2*-12}=\frac{-30-2\sqrt{249}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+2\sqrt{249}}{2*-12}=\frac{-30+2\sqrt{249}}{-24}
$