2/3x+8=7(4x-2)

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Solution for 2/3x+8=7(4x-2) equation: 


x in (-oo:+oo)

(2/3)*x+8 = 7*(4*x-2) // - 7*(4*x-2)

(2/3)*x-(7*(4*x-2))+8 = 0

(2/3)*x-7*(4*x-2)+8 = 0

(2*x)/3-7*(4*x-2)+8 = 0

(-7*3*(4*x-2))/3+(2*x)/3+(3*8)/3 = 0

2*x-7*3*(4*x-2)+3*8 = 0

24-82*x+42 = 0

66-82*x = 0

(66-82*x)/3 = 0

(66-82*x)/3 = 0 // * 3

66-82*x = 0

66-82*x = 0 // - 66

-82*x = -66 // : -82

x = -66/(-82)

x = 33/41

x = 33/41

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