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2/3x-1/2=1/5x+2
We move all terms to the left:
2/3x-1/2-(1/5x+2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x+2)!=0We get rid of parentheses
x∈R
2/3x-1/5x-2-1/2=0
We calculate fractions
(-75x^2)/60x^2+40x/60x^2+(-12x)/60x^2-2=0
We multiply all the terms by the denominator
(-75x^2)+40x+(-12x)-2*60x^2=0
Wy multiply elements
(-75x^2)-120x^2+40x+(-12x)=0
We get rid of parentheses
-75x^2-120x^2+40x-12x=0
We add all the numbers together, and all the variables
-195x^2+28x=0
a = -195; b = 28; c = 0;
Δ = b2-4ac
Δ = 282-4·(-195)·0
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-28}{2*-195}=\frac{-56}{-390} =28/195 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+28}{2*-195}=\frac{0}{-390} =0 $
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