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2/3x-1/5x=7
We move all terms to the left:
2/3x-1/5x-(7)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
10x/15x^2+(-3x)/15x^2-7=0
We multiply all the terms by the denominator
10x+(-3x)-7*15x^2=0
Wy multiply elements
-105x^2+10x+(-3x)=0
We get rid of parentheses
-105x^2+10x-3x=0
We add all the numbers together, and all the variables
-105x^2+7x=0
a = -105; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-105)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-105}=\frac{-14}{-210} =1/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-105}=\frac{0}{-210} =0 $
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