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2/3x-1/6=3/2x
We move all terms to the left:
2/3x-1/6-(3/2x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x-(+3/2x)-1/6=0
We get rid of parentheses
2/3x-3/2x-1/6=0
We calculate fractions
(-12x^2)/216x^2+144x/216x^2+(-324x)/216x^2=0
We multiply all the terms by the denominator
(-12x^2)+144x+(-324x)=0
We get rid of parentheses
-12x^2+144x-324x=0
We add all the numbers together, and all the variables
-12x^2-180x=0
a = -12; b = -180; c = 0;
Δ = b2-4ac
Δ = -1802-4·(-12)·0
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-180}{2*-12}=\frac{0}{-24} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+180}{2*-12}=\frac{360}{-24} =-15 $
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