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2/3x-24=1/5x-6
We move all terms to the left:
2/3x-24-(1/5x-6)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x-6)!=0We get rid of parentheses
x∈R
2/3x-1/5x+6-24=0
We calculate fractions
10x/15x^2+(-3x)/15x^2+6-24=0
We add all the numbers together, and all the variables
10x/15x^2+(-3x)/15x^2-18=0
We multiply all the terms by the denominator
10x+(-3x)-18*15x^2=0
Wy multiply elements
-270x^2+10x+(-3x)=0
We get rid of parentheses
-270x^2+10x-3x=0
We add all the numbers together, and all the variables
-270x^2+7x=0
a = -270; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·(-270)·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*-270}=\frac{-14}{-540} =7/270 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*-270}=\frac{0}{-540} =0 $
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