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2/3x-3(x+1)=-2x-1/3(6-x)
We move all terms to the left:
2/3x-3(x+1)-(-2x-1/3(6-x))=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 3(6-x))!=0We add all the numbers together, and all the variables
x∈R
2/3x-3(x+1)-(-2x-1/3(-1x+6))=0
We multiply parentheses
2/3x-3x-(-2x-1/3(-1x+6))-3=0
We calculate fractions
-3x+(6x(-)/(9x^2(-)+(-(-2x-1*3x)/(9x^2(-)-3=0
We can not solve this equation
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