2/3x-3/4(x+1)=1/6x-41/16

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Solution for 2/3x-3/4(x+1)=1/6x-41/16 equation:


x in (-oo:+oo)

(2/3)*x-((3/4)*(x+1)) = (1/6)*x-(41/16) // - (1/6)*x-(41/16)

(2/3)*x-((3/4)*(x+1))-((1/6)*x)+41/16 = 0

(-3/4)*(x+1)+(2/3)*x+(-1/6)*x+41/16 = 0

(2*x)/3-3/4*(x+1)-x/6+41/16 = 0

(-3/4*3*6*16*(x+1))/(3*6*16)+(2*6*16*x)/(3*6*16)+(3*16*(-x))/(3*6*16)+(3*6*41)/(3*6*16) = 0

2*6*16*x-3/4*3*6*16*(x+1)+3*16*(-x)+3*6*41 = 0

738-24*x-48*x-216 = 0

738-72*x-216 = 0

522-72*x = 0

(522-72*x)/(3*6*16) = 0

(522-72*x)/(3*6*16) = 0 // * 3*6*16

522-72*x = 0

522-72*x = 0 // - 522

-72*x = -522 // : -72

x = -522/(-72)

x = 29/4

x = 29/4

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