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2/3x-3=-1/2x-6
We move all terms to the left:
2/3x-3-(-1/2x-6)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x-6)!=0We get rid of parentheses
x∈R
2/3x+1/2x+6-3=0
We calculate fractions
4x/6x^2+3x/6x^2+6-3=0
We add all the numbers together, and all the variables
4x/6x^2+3x/6x^2+3=0
We multiply all the terms by the denominator
4x+3x+3*6x^2=0
We add all the numbers together, and all the variables
7x+3*6x^2=0
Wy multiply elements
18x^2+7x=0
a = 18; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·18·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*18}=\frac{-14}{36} =-7/18 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*18}=\frac{0}{36} =0 $
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