2/3x-3=-2x+5

Solution for 2/3x-3=-2x+5 equation:

2/3x-3=-2x+5

We move all terms to the left:

2/3x-3-(-2x+5)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We get rid of parentheses

2/3x+2x-5-3=0

We multiply all the terms by the denominator


2x*3x-5*3x-3*3x+2=0

Wy multiply elements

6x^2-15x-9x+2=0

We add all the numbers together, and all the variables

6x^2-24x+2=0

a = 6; b = -24; c = +2;
Δ = b2-4ac
Δ = -242-4·6·2
Δ = 528
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{528}=\sqrt{16*33}=\sqrt{16}*\sqrt{33}=4\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{33}}{2*6}=\frac{24-4\sqrt{33}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{33}}{2*6}=\frac{24+4\sqrt{33}}{12}
$