2/3x-3x-3=-2x-2+1/3x

Solution for 2/3x-3x-3=-2x-2+1/3x equation:

2/3x-3x-3=-2x-2+1/3x

We move all terms to the left:

2/3x-3x-3-(-2x-2+1/3x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-3x-(-2x+1/3x-2)-3=0

We add all the numbers together, and all the variables

-3x+2/3x-(-2x+1/3x-2)-3=0

We get rid of parentheses

-3x+2/3x+2x-1/3x+2-3=0

We multiply all the terms by the denominator


-3x*3x+2x*3x+2*3x-3*3x+2-1=0

We add all the numbers together, and all the variables

-3x*3x+2x*3x+2*3x-3*3x+1=0

Wy multiply elements

-9x^2+6x^2+6x-9x+1=0

We add all the numbers together, and all the variables

-3x^2-3x+1=0

a = -3; b = -3; c = +1;
Δ = b2-4ac
Δ = -32-4·(-3)·1
Δ = 21
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{21}}{2*-3}=\frac{3-\sqrt{21}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{21}}{2*-3}=\frac{3+\sqrt{21}}{-6}
$