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2/3x-3x=-21
We move all terms to the left:
2/3x-3x-(-21)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-3x+2/3x+21=0
We multiply all the terms by the denominator
-3x*3x+21*3x+2=0
Wy multiply elements
-9x^2+63x+2=0
a = -9; b = 63; c = +2;
Δ = b2-4ac
Δ = 632-4·(-9)·2
Δ = 4041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4041}=\sqrt{9*449}=\sqrt{9}*\sqrt{449}=3\sqrt{449}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-3\sqrt{449}}{2*-9}=\frac{-63-3\sqrt{449}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+3\sqrt{449}}{2*-9}=\frac{-63+3\sqrt{449}}{-18} $
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