2/3x-4+1=x-2

Solution for 2/3x-4+1=x-2 equation:

2/3x-4+1=x-2

We move all terms to the left:

2/3x-4+1-(x-2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(x-2)-3=0

We get rid of parentheses

2/3x-x+2-3=0

We multiply all the terms by the denominator


-x*3x+2*3x-3*3x+2=0

Wy multiply elements

-3x^2+6x-9x+2=0

We add all the numbers together, and all the variables

-3x^2-3x+2=0

a = -3; b = -3; c = +2;
Δ = b2-4ac
Δ = -32-4·(-3)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{33}}{2*-3}=\frac{3-\sqrt{33}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{33}}{2*-3}=\frac{3+\sqrt{33}}{-6}
$