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2/3x-41/2x=-8
We move all terms to the left:
2/3x-41/2x-(-8)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2/3x-41/2x+8=0
We calculate fractions
4x/6x^2+(-123x)/6x^2+8=0
We multiply all the terms by the denominator
4x+(-123x)+8*6x^2=0
Wy multiply elements
48x^2+4x+(-123x)=0
We get rid of parentheses
48x^2+4x-123x=0
We add all the numbers together, and all the variables
48x^2-119x=0
a = 48; b = -119; c = 0;
Δ = b2-4ac
Δ = -1192-4·48·0
Δ = 14161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14161}=119$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-119)-119}{2*48}=\frac{0}{96} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-119)+119}{2*48}=\frac{238}{96} =2+23/48 $
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