2/3x-4=1/6x-3

Solution for 2/3x-4=1/6x-3 equation:

2/3x-4=1/6x-3

We move all terms to the left:

2/3x-4-(1/6x-3)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x-3)!=0

x∈R


We get rid of parentheses

2/3x-1/6x+3-4=0

We calculate fractions


12x/18x^2+(-3x)/18x^2+3-4=0

We add all the numbers together, and all the variables

12x/18x^2+(-3x)/18x^2-1=0

We multiply all the terms by the denominator


12x+(-3x)-1*18x^2=0

Wy multiply elements

-18x^2+12x+(-3x)=0

We get rid of parentheses

-18x^2+12x-3x=0

We add all the numbers together, and all the variables

-18x^2+9x=0

a = -18; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·(-18)·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*-18}=\frac{-18}{-36}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*-18}=\frac{0}{-36}
=0
$