2/3x-4=5+4/6x

Solution for 2/3x-4=5+4/6x equation:

2/3x-4=5+4/6x

We move all terms to the left:

2/3x-4-(5+4/6x)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 6x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x-(4/6x+5)-4=0

We get rid of parentheses

2/3x-4/6x-5-4=0

We calculate fractions


12x/18x^2+(-12x)/18x^2-5-4=0

We add all the numbers together, and all the variables

12x/18x^2+(-12x)/18x^2-9=0

We multiply all the terms by the denominator


12x+(-12x)-9*18x^2=0

Wy multiply elements

-162x^2+12x+(-12x)=0

We get rid of parentheses

-162x^2+12x-12x=0

We add all the numbers together, and all the variables

-162x^2=0

a = -162; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-162)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-324}=0$