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2/3x-5+4/5x=-2
We move all terms to the left:
2/3x-5+4/5x-(-2)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
2/3x+4/5x-3=0
We calculate fractions
10x/15x^2+12x/15x^2-3=0
We multiply all the terms by the denominator
10x+12x-3*15x^2=0
We add all the numbers together, and all the variables
22x-3*15x^2=0
Wy multiply elements
-45x^2+22x=0
a = -45; b = 22; c = 0;
Δ = b2-4ac
Δ = 222-4·(-45)·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-22}{2*-45}=\frac{-44}{-90} =22/45 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+22}{2*-45}=\frac{0}{-90} =0 $
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