2/3x-5/8x=2

Solution for 2/3x-5/8x=2 equation:

2/3x-5/8x=2

We move all terms to the left:

2/3x-5/8x-(2)=0


Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R


We calculate fractions


16x/24x^2+(-15x)/24x^2-2=0

We multiply all the terms by the denominator


16x+(-15x)-2*24x^2=0

Wy multiply elements

-48x^2+16x+(-15x)=0

We get rid of parentheses

-48x^2+16x-15x=0

We add all the numbers together, and all the variables

-48x^2+x=0

a = -48; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-48)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-48}=\frac{-2}{-96}
=1/48
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-48}=\frac{0}{-96}
=0
$