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2/3x-5=8+5/6x
We move all terms to the left:
2/3x-5-(8+5/6x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 6x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x-(5/6x+8)-5=0
We get rid of parentheses
2/3x-5/6x-8-5=0
We calculate fractions
12x/18x^2+(-15x)/18x^2-8-5=0
We add all the numbers together, and all the variables
12x/18x^2+(-15x)/18x^2-13=0
We multiply all the terms by the denominator
12x+(-15x)-13*18x^2=0
Wy multiply elements
-234x^2+12x+(-15x)=0
We get rid of parentheses
-234x^2+12x-15x=0
We add all the numbers together, and all the variables
-234x^2-3x=0
a = -234; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-234)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-234}=\frac{0}{-468} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-234}=\frac{6}{-468} =-1/78 $
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