2/3x-7/4=4/3x-23(x+5)

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Solution for 2/3x-7/4=4/3x-23(x+5) equation: 



2/3x-7/4=4/3x-23(x+5)

We move all terms to the left:

2/3x-7/4-(4/3x-23(x+5))=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x-23(x+5))!=0

x∈R



We calculate fractions


(-(4*3x*4)/(9x^2-92x)+(-189x^2-23x)/(9x^2-92x)+(-86x)/(9x^2-92x)=0



We calculate terms in parentheses: +(-(4*3x*4)/(9x^2-92x)+(-189x^2-23x)/(9x^2-92x)+(-86x)/(9x^2-92x), so:

-(4*3x*4)/(9x^2-92x)+(-189x^2-23x)/(9x^2-92x)+(-86x)/(9x^2-92x

determiningTheFunctionDomain
(-189x^2-23x)/(9x^2-92x)-(4*3x*4)/(9x^2-92x)+(-86x)/(9x^2-92x

We add all the numbers together, and all the variables

(-189x^2-23x)/(9x^2-92x)-(+4*3x*4)/(9x^2-92x)+(-86x)/(9x^2-92x

We calculate fractions


(-189x^2-23x-(+4*3x*4)*(9x^2-92x)/((9x^2-92x)*(9x^2-92x)+((-86x)*(9x^2-92x))/((9x^2-92x)*(9x^2-92x)



We calculate terms in parentheses: +(-189x^2-23x-(+4*3x*4)*(9x^2-92x)/((9x^2-92x)*(9x^2-92x)+((-86x)*(9x^2-92x))/((9x^2-92x)*(9x^2-92x), so:

-189x^2-23x-(+4*3x*4)*(9x^2-92x)/((9x^2-92x)*(9x^2-92x)+((-86x)*(9x^2-92x))/((9x^2-92x)*(9x^2-92x

We can not solve this equation

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