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2/3x-7=2x+3
We move all terms to the left:
2/3x-7-(2x+3)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-2x-3-7=0
We multiply all the terms by the denominator
-2x*3x-3*3x-7*3x+2=0
Wy multiply elements
-6x^2-9x-21x+2=0
We add all the numbers together, and all the variables
-6x^2-30x+2=0
a = -6; b = -30; c = +2;
Δ = b2-4ac
Δ = -302-4·(-6)·2
Δ = 948
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{948}=\sqrt{4*237}=\sqrt{4}*\sqrt{237}=2\sqrt{237}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-2\sqrt{237}}{2*-6}=\frac{30-2\sqrt{237}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+2\sqrt{237}}{2*-6}=\frac{30+2\sqrt{237}}{-12} $
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