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2/3x^2+x/2=x+5/x
We move all terms to the left:
2/3x^2+x/2-(x+5/x)=0
Domain of the equation: 3x^2!=0
x^2!=0/3
x^2!=√0
x!=0
x∈R
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/3x^2+x/2-(+x+5/x)=0
We get rid of parentheses
2/3x^2+x/2-x-5/x=0
We calculate fractions
We do not support expression: x^3
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