2/3x2-7=47

Solution for 2/3x2-7=47 equation:

2/3x^2-7=47

We move all terms to the left:

2/3x^2-7-(47)=0


Domain of the equation: 3x^2!=0

x^2!=0/3

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

2/3x^2-54=0

We multiply all the terms by the denominator


-54*3x^2+2=0

Wy multiply elements

-162x^2+2=0

a = -162; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-162)·2
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-162}=\frac{-36}{-324}
=1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-162}=\frac{36}{-324}
=-1/9
$