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2/3x=1/9+x
We move all terms to the left:
2/3x-(1/9+x)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 9+x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x)!=-9
x!=-9/1
x!=-9
x∈R
2/3x-(+x+1/9)=0
We get rid of parentheses
2/3x-x-1/9=0
We calculate fractions
There is no solution for this equation
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