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2/3x=5x-4
We move all terms to the left:
2/3x-(5x-4)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-5x+4=0
We multiply all the terms by the denominator
-5x*3x+4*3x+2=0
Wy multiply elements
-15x^2+12x+2=0
a = -15; b = 12; c = +2;
Δ = b2-4ac
Δ = 122-4·(-15)·2
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{66}}{2*-15}=\frac{-12-2\sqrt{66}}{-30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{66}}{2*-15}=\frac{-12+2\sqrt{66}}{-30} $
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