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2/3x=90-x
We move all terms to the left:
2/3x-(90-x)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
2/3x-(-1x+90)=0
We get rid of parentheses
2/3x+1x-90=0
We multiply all the terms by the denominator
1x*3x-90*3x+2=0
Wy multiply elements
3x^2-270x+2=0
a = 3; b = -270; c = +2;
Δ = b2-4ac
Δ = -2702-4·3·2
Δ = 72876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{72876}=\sqrt{4*18219}=\sqrt{4}*\sqrt{18219}=2\sqrt{18219}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-270)-2\sqrt{18219}}{2*3}=\frac{270-2\sqrt{18219}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-270)+2\sqrt{18219}}{2*3}=\frac{270+2\sqrt{18219}}{6} $
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