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2/3x=9x-1
We move all terms to the left:
2/3x-(9x-1)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
2/3x-9x+1=0
We multiply all the terms by the denominator
-9x*3x+1*3x+2=0
Wy multiply elements
-27x^2+3x+2=0
a = -27; b = 3; c = +2;
Δ = b2-4ac
Δ = 32-4·(-27)·2
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-15}{2*-27}=\frac{-18}{-54} =1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+15}{2*-27}=\frac{12}{-54} =-2/9 $
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