2/3y+14=-1/6y-8

Solution for 2/3y+14=-1/6y-8 equation:

2/3y+14=-1/6y-8

We move all terms to the left:

2/3y+14-(-1/6y-8)=0


Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: 6y-8)!=0

y∈R


We get rid of parentheses

2/3y+1/6y+8+14=0

We calculate fractions


12y/18y^2+3y/18y^2+8+14=0

We add all the numbers together, and all the variables

12y/18y^2+3y/18y^2+22=0

We multiply all the terms by the denominator


12y+3y+22*18y^2=0

We add all the numbers together, and all the variables

15y+22*18y^2=0

Wy multiply elements

396y^2+15y=0

a = 396; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·396·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*396}=\frac{-30}{792}
=-5/132
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*396}=\frac{0}{792}
=0
$